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7r^2-6=477
We move all terms to the left:
7r^2-6-(477)=0
We add all the numbers together, and all the variables
7r^2-483=0
a = 7; b = 0; c = -483;
Δ = b2-4ac
Δ = 02-4·7·(-483)
Δ = 13524
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13524}=\sqrt{196*69}=\sqrt{196}*\sqrt{69}=14\sqrt{69}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{69}}{2*7}=\frac{0-14\sqrt{69}}{14} =-\frac{14\sqrt{69}}{14} =-\sqrt{69} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{69}}{2*7}=\frac{0+14\sqrt{69}}{14} =\frac{14\sqrt{69}}{14} =\sqrt{69} $
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